NaOH + HCl = NaCl + H2O
n(NaOH) = C(NaOH)*V(NaOH) = 1.25 M * 0.0188 L = 0.0235 moles
n(HCl) = n(NaOH) = 0.0235 moles
C(HCl) = n(HCl) / V(HCl) = 0.0235 moles / 0.025 L = 0.94 M
ω(HCl) = (C(HCl) * Mr(HCl) / (ρ(HCl)*1000)) * 100% = (0.94 M * 36.5 g/mol) / (1.02 g/ml * 1000) = 0.0336 * 100% = 3.36 %
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