Mass of CuSO4● XH2O (g) = 1.6 grams BEFORE HEATING
After Heating :
Mass of H2O(g) = 1.1g
Mass of CuSO4 (g) : 0.5
QUESTION:
Use the information to calculate the number of moles of water lost and the number of moles in the anhydrous compound
"M(H_2O)=2x1+16=18 g\/mole"
"n(H_2O)=1.1\/18=0.061 mole"
"M(CuSO_4)=64+32+4x16=160 g\/mole"
"n(CuSO_4)=0.5\/160=0.0031 mole"
"n(H_2O)\/n(CuSO_4)=0.061\/0.0031=20"
So formula is "CuSO_4x20H_2O"
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