Question #340568

Mass of CuSO4● XH2O (g) = 1.6 grams BEFORE HEATING

After Heating :

Mass of H2O(g) = 1.1g

Mass of CuSO4 (g) : 0.5


QUESTION:

Use the information to calculate the number of moles of water lost and the number of moles in the anhydrous compound



1
Expert's answer
2022-05-16T10:27:03-0400

M(H2O)=2x1+16=18g/moleM(H_2O)=2x1+16=18 g/mole

n(H2O)=1.1/18=0.061molen(H_2O)=1.1/18=0.061 mole

M(CuSO4)=64+32+4x16=160g/moleM(CuSO_4)=64+32+4x16=160 g/mole

n(CuSO4)=0.5/160=0.0031molen(CuSO_4)=0.5/160=0.0031 mole

n(H2O)/n(CuSO4)=0.061/0.0031=20n(H_2O)/n(CuSO_4)=0.061/0.0031=20

So formula is CuSO4x20H2OCuSO_4x20H_2O



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