Mass of CuSO4● XH2O (g) = 1.6 grams BEFORE HEATING
After Heating :
Mass of H2O(g) = 1.1g
Mass of CuSO4 (g) : 0.5
QUESTION:
Use the information to calculate the number of moles of water lost and the number of moles in the anhydrous compound
M(H2O)=2x1+16=18g/moleM(H_2O)=2x1+16=18 g/moleM(H2O)=2x1+16=18g/mole
n(H2O)=1.1/18=0.061molen(H_2O)=1.1/18=0.061 molen(H2O)=1.1/18=0.061mole
M(CuSO4)=64+32+4x16=160g/moleM(CuSO_4)=64+32+4x16=160 g/moleM(CuSO4)=64+32+4x16=160g/mole
n(CuSO4)=0.5/160=0.0031molen(CuSO_4)=0.5/160=0.0031 molen(CuSO4)=0.5/160=0.0031mole
n(H2O)/n(CuSO4)=0.061/0.0031=20n(H_2O)/n(CuSO_4)=0.061/0.0031=20n(H2O)/n(CuSO4)=0.061/0.0031=20
So formula is CuSO4x20H2OCuSO_4x20H_2OCuSO4x20H2O
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