The reaction 2 NO(g) ---- N2(g)+O2(g) has a Kc value of 2400 at 2000 K. If 0.850 M each of N2 and O2 are initially present in a 3.00-L vessel, calculate the equilibrium of No, N2 and O2
Ka = products / reactants
= (O2)(N2)/NO
0.850/3 = 0.283 m/L
Initial concentration = 0.283m/L
2400 =2000× 0.283 × X
2400 = 566X
X = 2400/566
= 4.24m/L
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