pOH = 14 - pH
pH = - log [HCl] = - log 1.4 x 10-3 =2.85
pOH = 14 -2.85 = 11.15
[OH-] = 7.08 х 10 -12
pOH= pKb + log[salt]/[Acid]
Kb of NH3 is 1.8x10-5
pKb= -logKb = -log(1.8x10-5) = 4.745
pOH= 4.745 + log(0.35/0.15) = 4.38
pH = 14 - pOH = 14 - 4.38 = 9.62
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