At equilibrium the concentrations in moles/L of N2, H2, and NH3 at 300 C are 0.25, 0.15, and 0.90 respectively. Find K for the reaction N2 + H2 ----- NH3
DEADLINE : 05/13/2022 11 : 00 PM
"N_2+3H_2= 2NH_3"
"K=\\frac{[NH_3]^2}{[N_2][H_2]^3}=\\frac{0.90^2}{0.25 \\times 0.15^3} = 0.011 L^2 mol^{-2}"
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