Question

What mass of hydrogen peroxide must decompose to produce 65.88 g of H2O

Answer 1

$2H_2O_2\rightarrow 2H_2O + O_2$

$M(H_2O)=2x1+16=18 g/mole$

$n(H_2O)=65.88/18=3.66 mole$

$n(H_2O_2)=n(H_2O)=3.66 mole$

$M(H_2O_2)=2x1+2x16=34 g/mole$

$m(H_2O_2)=34x3.66=124.44 g$