A gas has a volume of 28 liters at STP. Calculate the pressure if the temperature is increased to 35°C and the volume is decreased to 15 liters
V1=28 l=0.028 m3
T1=273 K
P1=101325 Pa
V2=15 l=0.015 m3
T2=35 °C=308 K
P2-?
R=8.31 J/(mole K)
PV=nRT
"n=\\frac{P_1V_1}{RT_1}=\\frac{101325x0.028}{8.31x273}=1.25 mole"
"P_2=\\frac{nRT_2}{V_2}=\\frac{1.25x8.31x308}{0.015}=213389 Pa"
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