Question

A gas has a volume of 28 liters at STP. Calculate the pressure if the temperature is increased to 35°C and the volume is decreased to 15 liters

Answer 1

V₁=28 l=0.028 m³

T₁=273 K

P₁=101325 Pa

V₂=15 l=0.015 m³

T₂=35 °C=308 K

P₂-?

R=8.31 J/(mole K)

PV=nRT

$n=\frac{P_1V_1}{RT_1}=\frac{101325x0.028}{8.31x273}=1.25 mole$

$P_2=\frac{nRT_2}{V_2}=\frac{1.25x8.31x308}{0.015}=213389 Pa$