Answer to Question #340058 in General Chemistry for bse

Question

What mass of silver metal is produced from an excess of copper wire added to 4.92g of AgNO3?

Answer 1

Solution:

The molar mass of AgNO₃ is 169.87 g/mol

Therefore,

Moles of AgNO₃ = (4.92 g AgNO₃) × (1 mol AgNO₃ / 169.87 g AgNO₃) = 0.02896 mol AgNO₃

Balanced chemical equation:

2AgNO₃ + Cu → Cu(NO₃)₂ + 2Ag

According to stoichiometry:

2 mol of AgNO₃ produce 2 mol of Ag

Thus, 0.02896 mol of AgNO₃ produce:

(0.02896 mol AgNO₃) × (2 mol Ag / 2 mol AgNO₃) = 0.02896 mol Ag

The molar mass of Ag is 107.868 g/mol

Therefore,

Mass of Ag = (0.02896 mol Ag) × (107.868 g Ag / 1 mol Ag) = 3.1238 g Ag = 3.12 Ag

Mass of Ag = 3.12

Answer: 3.12 grams of silver metal is produced