Question #339839

What is the pH of a solution with [H^+] of 1.0 x 10^9M? What is its pOH? (Kw = [H^+][OH^-])


Expert's answer

pH=ln[H+]=ln(1.0x109)=9pH=-ln [H^+]=-ln(1.0 x 10^9)=-9

pH+pOH=14

pOH=14+9=23



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