What is the pH of a solution with [H^+] of 1.0 x 10^9M? What is its pOH? (Kw = [H^+][OH^-])
pH=−ln[H+]=−ln(1.0x109)=−9pH=-ln [H^+]=-ln(1.0 x 10^9)=-9pH=−ln[H+]=−ln(1.0x109)=−9
pH+pOH=14
pOH=14+9=23
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