Answer to Question #339780 in General Chemistry for Thel

Question

A mixture of 0.100 mol of NO, 0.050 mol of H2 and 0.10 mol of H2O is placed in a 1.0L vessel at 300 K. The following equilibrium is established: 2 NO(g) + 2 H2O(g). At equilibrium [NO] = 0.062 M. Calculate the equilibrium concentrations of H2O

Answer 1

$n(NO)=n(H_2O)=0.062 M$