A mixture of 0.100 mol of NO, 0.050 mol of H2 and 0.10 mol of H2O is placed in a 1.0L vessel at 300 K. The following equilibrium is established: 2 NO(g) + 2 H2O(g). At equilibrium [NO] = 0.062 M. Calculate the equilibrium concentrations of N2
[H2] = 0.012 M
[N2] = 0.019 M
[H2O] = 0.057 M
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