if I contain 3 moles of gas in a container with a volume of 60 liters and at a temperature of 400K, what is the pressure inside the container?
PV=nRT
P=nRT/V
n=3 mole
V=60 l=0.06 m3
R=8.31 J/(mole K)
T=400 K
P=3(8.31)400/0.06=166200 Pa
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