Answer to Question #338206 in General Chemistry for Sakina

General Chemistry

Question #338206

How many moles are in 50.4g of CaBr2

Expert's answer

n(CaBr₂) = m(CaBr₂)/Mr(CaBr₂)

n(CaBr₂) = 50.4 g / 199.89 g/mol = 0.252 moles

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