Answer to Question #338206 in General Chemistry for Sakina

Question #338206

How many moles are in 50.4g of CaBr2


1
Expert's answer
2022-05-09T10:31:03-0400

n(CaBr2) = m(CaBr2)/Mr(CaBr2)

n(CaBr2) = 50.4 g / 199.89 g/mol = 0.252 moles


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