if 100cm of hydrogen is sparked with 40cm3 of oxygen to produce H2O at s.t.p, calculate the volume of the gas that is in excess
2H2 + O2 =2 H2O
n(H2) = 0.1 L / 2*22.4 mol/L = 0.0022 moles
n(O2) = 0.04 L / 22.4 mol/L = 0.0017 moles
H2 - is in excess
V (H2) =( 0.04L • 2•22.4 mol/L) / 22.4 mol/L = 0.08 L
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