Answer to Question #337291 in General Chemistry for Ellie

Question

nitric oxide?

What mass of CaH3N can be made when 21.6 g of CaH6 react with 21.6 g of

Answer 1

4C₃H₆₍g) + 6NO(g) → 4C₃H₃N(s) + 6H₂O(l) + N₂(g)

n(C₃H₆)=m(C₃H₆)/M(C₃H₆) =21.6 g/42.08 g/mol=0.513 mol

n(NO)=m(NO)/M(NO) =21.6 g/30.01 g/mol = 0.720 mol

n(C₃H₆)/4=0.128 mol;

n(NO)/6=0.120 mol

So NO is the limiting reactant.

n(C₃H₃N)=4/6 n(NO)=0.480 mol

m(C₃H₃N)=n(C₃H₃N)×M(C₃H₃N)=0.480 mol ×53.06 g/mol = 25.5 g