Answer to Question #337278 in General Chemistry for Jacalin

Question

What is the pressure of 3.5 miles of gas at 1.1 kilo pascals and 420 Kel

Answer 1

PV = nRT

T = 420 K

n = 3,5 moll

R = 8.314 m³•Pa/K•moll

P = 1.1 kPa = 1100 Pa - the pressure

mayby you must you had to find the volume of gas

V = nRT/P = (3.5 mol • 8.314 m³•Pa/K•moll • 420 K) / 1100 Pa = 11.11 m³