At what temperature in Fahrenheit will a 830grams Carbon dioxide occupies a volume of 390L at 1900 torr?
PV = nRT, T = PV/nR
P = 1900 torr = 2.5 atm
T(CO2) = (2.5 atm * 390L) / ((830g / 44g/mol) * 0,082 atm·L/K·mol)) = 630.45 K
T(CO2) = 630.45 K = 675,14 °F
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