Answer to Question #337087 in General Chemistry for Cosmo

General Chemistry

Question #337087

A 2.00 Liter container of nitrogen had a pressure of 3.20atm. What volume would it be 692 torr?

Expert's answer

P₁V₁ = P₂V₂

V₂= P₁V₁ / P₂

P₂ = 692 torr = 0.91 atm

V₂ = (3.20 atm * 2.00 L) / 0.91 atm = 7.03 L

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