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Answer to Question #337087 in General Chemistry for Cosmo

Question #337087

A 2.00 Liter container of nitrogen had a pressure of 3.20atm. What volume would it be 692 torr?


1
Expert's answer
2022-05-05T03:25:03-0400

P1V1 = P2V2

V2 = P1V1 / P2

P2 = 692 torr = 0.91 atm


V2 = (3.20 atm * 2.00 L) / 0.91 atm = 7.03 L

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