A sample of nitrogen occupies a volume of 250 mL at 25 C. What volume will it occupy at 0C?
V1/T1 = V2/T2
V2 = (V1/T1) * T2
V1 = 250 mL = 0.25 L, T1 = 25°C = 298.15 K, T2 = 0°C = 273.15 K
V2 = (0.25 L / 298.15 K) * 273.15 K = 0,229 L = 229 Â mL
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