Question

Calculate the standard heat of vaporization, △Hvap, for tin(IV) chloride, SnCl4.

△H°f = -511.3 kJ/mol for SnCl4(l) and -471.5 kJ/mol for SnCl4(g). Show your work.

Answer 1

$SnCl_4(l) \rightarrow SnCl_4(g)$

$\Delta H_{evap}=\Delta HSnCl_4(g)- \Delta HSnCl_4(l)=-471.5-(-511.3)=39.8kJ/mol$