Question #336690
If I start with .713 moles of hydrogen and excess bromine, how many moles of hydrogen bormide can I make?
Expert's answer
H2 + Br2 = 2HBr
1.426 mol
If I start with .713 moles of hydrogen and excess bromine, how many moles of hydrogen bormide can I make?
H2 + Br2 = 2HBr
1.426 mol
