Answer to Question #336591 in General Chemistry for Siyabonga

Question

What is the molarity of glacial acetic acid (CH3COOH, Mr = 60.05 g/mol) at 25°C given that the density of acetic acid at that temperature is 1.049 g/mL?

[1] 0.0174 M

[2] 0.057 M [3] 57.2 M

[4] 60.1 M

[5] None of the above

Answer 1

Solution:

Molarity is moles of solute per liter of solution.

So, assume you have 1 L (1000 mL) of glacial acetic acid, which is pure acetic acid.

The mass of that is (1000 mL) × (1.049 g/mL) = 1049 g

Moles of acetic acid = (1049 g) / (60.05 g/mol) = 17.47 mol

So, the molarity is 17.47 M

Answer: [5] None of the above