Answer to Question #336590 in General Chemistry for Siyabonga

Question

25.00 cm3 of a 0.7892 mol.dm-3 solution of potassium hydroxide is transferred to an empty 350.00 cm3 volumetric flask. This flask is made up to the mark with distilled water and then shaken well. The concentration of the potassium hydroxide in this second flask is:

[1] 0.01109 mol.dm-3

[2] 0.05637 mol.dm-3

[3] 0.7892 mol.dm-3

[4] 17.74 mol.dm-3

[5] None of the above.

Answer 1

Solution:

Concentration of KOH = (25.00 cm³ / 350.00 cm³) × (0.7892 mol dm⁻³) = 0.05637 mol dm⁻³

Concentration of KOH = 0.05637 mol dm⁻³

Answer: [2] 0.05637 mol dm⁻³