Answer to Question #336049 in General Chemistry for hoshi

Question

Convert the following concentrations of aqueous solutions.

1.00m K₂SO_4(aq) %(w/w) FW (K₂SO₄)=174.26 g/mol

Answer 1

1.00 means that 1 l of solution contain s 1 mole of $K_2SO_4$

Density of water us nearly 1 g/ml, so 1 l os solution has mass 1000 g.

$m(K_2SO_4)=174.26x1=174.26 g$

$w(K_2SO_4)=174.26x100/1000=17.426\%$