Answer to Question #336020 in General Chemistry for John

Question

If 15.0 mol of C₃H₈ react with 4.5 mol of O₂ which is the limiting reagent? Which is the excess reagent?

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DEADLINE : 05/02/2022 11 : 00 PM

Answer 1

Solution:

Balanced chemical equation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

According to stoichiometry:

1 mol of C₃H₈ reacts with 5 mol of O₂

Thus, 15.0 mol of C₃H₈ react with:

(15.0 mol C₃H₈) × (5 mol O₂ / 1 mol C₃H₈) = 75 mol O₂

However, initially there is 4.5 mol of O₂ (according to the task).

Therefore, O₂ acts as limiting reagent and C₃H₈ is excess reagent.

Answer:

The limiting reagent is O₂

The excess reagent is C₃H₈