How many particles are in 2.5 x10 -3 kiloliters of Ammonium Chromate?
2.5x10−3kiloliters=2.5l=2500ml2.5 x10^{-3} kiloliters=2.5 l=2500 ml2.5x10−3kiloliters=2.5l=2500ml
Density is 1.9 g/ml
m((NH4)2CrO4)=1.9x2500=4750gm((NH_4)_2CrO_4)=1.9x2500=4750 gm((NH4)2CrO4)=1.9x2500=4750g
M((NH4)2CrO4)=2(14+1x4)+52+4x16=152g/molM((NH_4)_2CrO_4)=2(14+1x4)+52+4x16=152 g/molM((NH4)2CrO4)=2(14+1x4)+52+4x16=152g/mol
n((NH4)2CrO4)=4750/152=31.25moln((NH_4)_2CrO_4)=4750/152=31.25 moln((NH4)2CrO4)=4750/152=31.25mol
Number of particles is 31.25x6.02x1023=1.88x102531.25x6.02x10^{23}=1.88 x10^{25}31.25x6.02x1023=1.88x1025 particles
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