Answer to Question #335918 in General Chemistry for MORGAN

Question #335918

How many particles are in 2.5 x10 -3 kiloliters of Ammonium Chromate?


1
Expert's answer
2022-05-03T13:07:03-0400

2.5x103kiloliters=2.5l=2500ml2.5 x10^{-3} kiloliters=2.5 l=2500 ml

Density is 1.9 g/ml

m((NH4)2CrO4)=1.9x2500=4750gm((NH_4)_2CrO_4)=1.9x2500=4750 g

M((NH4)2CrO4)=2(14+1x4)+52+4x16=152g/molM((NH_4)_2CrO_4)=2(14+1x4)+52+4x16=152 g/mol

n((NH4)2CrO4)=4750/152=31.25moln((NH_4)_2CrO_4)=4750/152=31.25 mol

Number of particles is 31.25x6.02x1023=1.88x102531.25x6.02x10^{23}=1.88 x10^{25} particles





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