Answer to Question #335918 in General Chemistry for MORGAN

Question

How many particles are in 2.5 x10 -3 kiloliters of Ammonium Chromate?

Answer 1

$2.5 x10^{-3} kiloliters=2.5 l=2500 ml$

Density is 1.9 g/ml

$m((NH_4)_2CrO_4)=1.9x2500=4750 g$

$M((NH_4)_2CrO_4)=2(14+1x4)+52+4x16=152 g/mol$

$n((NH_4)_2CrO_4)=4750/152=31.25 mol$

Number of particles is $31.25x6.02x10^{23}=1.88 x10^{25}$ particles