Answer to Question #335691 in General Chemistry for Iddris

Question

Billions of pounds of urea are produced annually for use as a fertilizer

The reaction used is

2NH3+CO2=CO(NH2)2+H2O

The typical starting mixture has 3:1 mole ratio of NH3 to CO2 .If 47.7grams urea form per mole of CO2 that reacts what is the

A:Theoretical yield

B:Actual yield

Answer 1

The molecular formula of urea is N2H4CO and the molar mass is 60g/mol

1 mole of CO2 produced 60g of urea which is the actual yield of urea and 47.7g of urea is the theoretical yield.

The percentage yield of urea = 47.7×100%/60 = 79.5%