What mass of NH3(g) is produced when 2.15 L of H2(g) measured at STP reacts?
N2 + 3H2 ⇌ 2NH3
m(NH3) = (V(H2) • 2Mr(NH3)) / 3Vm
m(NH3) = (2.15 L • ( 2• 17.03 g/mol)) / 3•22.4 L/mol) = 1.09 g
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