Answer to Question #335236 in General Chemistry for Jordan

Question

What will the volume of a sample be if 335 mL of an ideal gas at 24 °C and 1.08 atm is cooled to 17 °C and 0.976 atm?

Answer 1

P₁ = 1.08 atm

V₁ = 335 mL

T₁ = 24°C + 273.15 = 297.15 K

P₂ = 0.976 atm

V₂ = ???

T₂ = 17°C + 273.15 = 290.15 K

Solution:

Mathematical expression for the combined gas law:

P₁V₁/T₁ = P₂V₂/T₂

Cross-multiply to clear the fractions:

P₁V₁T₂ = P₂V₂T₁

Divide to isolate V₂:

V₂ = (P₁V₁T₂) / (P₂T₁)

Plug in the numbers and solve for V₂:

V₂ = (1.08 atm × 335 mL × 290.15 K) / (0.976 atm × 297.15 K) = 361.964 mL = 362 mL

V₂ = 362 mL

Answer: The volume of a sample will be 362 mL