At what temperature will 4.15g of CO2 exert a pressure of 855 mmHg at a volume of 650 ml? (make sure to turn grams into moles)
Solution:
The molar mass of CO2 is 44.01 g/mol
Therefore,
Moles of CO2 = (4.15 g CO2) × (1 mol CO2 / 44.01 CO2) = 0.0943 mol CO2
Convert mmHg to atm:
1 atm = 760 mmHg
Therefore,
P = (855 mmHg) × (1 atm / 760 mmHg) = 1.125 atm
Convert mL to L:
1 L = 1000 mL
Therefore,
V = (650 mL) × (1 L / 1000 mL) = 0.65 L
R = gas constant = 0.082 L atm K−1 mol−1
Ideal gas law can be used to calculate the temperature:
PV = nRT
T = PV / nR
T = (1.125 atm × 0.65 L) / (0.0943 mol × 0.082 L atm K−1 mol−1) = 94.57 K
T = 94.57 K
Answer: at 94.57 K
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