What is the initial volume of a 12.1mol/L hcl solution needed in order 500.0ml of a 2.5 mol/l solution of hcl
The initial volume of the HCl 12.1 mol/L solution can be deduced from the statement of the moles number equality:
"n_1=n_2"
when "n" can be written in the following way:
"c_1V_1=c_2V_2"
"V_1=\\frac{c_2V_2}{c_1}=\\frac{2.5 mol\/L \\times 500.0 ml}{12.1 mol\/L} = 103.3 ml"
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