Answer to Question #334280 in General Chemistry for Sofia

Question #334280

The Δ𝐻vap of a certain compound is 10.14 kJ·mol−1 and its Δ𝑆vap is 78.22 J·mol −1·K−1.


What is the boiling point of this compound?


1
Expert's answer
2022-04-27T22:20:03-0400

Solution:

T = ΔH / ΔS = (10140 J mol−1) / (78.22 J mol−1 K−1) = 129.6 K

T = 129.6 K


Answer: The boiling point of this compound is 129.6 K

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