The Δ𝐻vap of a certain compound is 10.14 kJ·mol−1 and its Δ𝑆vap is 78.22 J·mol −1·K−1.
What is the boiling point of this compound?
Solution:
T = ΔH / ΔS = (10140 J mol−1) / (78.22 J mol−1 K−1) = 129.6 K
T = 129.6 K
Answer: The boiling point of this compound is 129.6 K
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