Question #333672

πŸπ‘Ίπ‘ΆπŸ(π’ˆ) + π‘ΆπŸ(π’ˆ) β‡Œ πŸπ‘Ίπ‘ΆπŸ‘(π’ˆ)

Kc = 6.1 x 104 at 750K. At equilibrium π‘·π‘Ίπ‘ΆπŸ = 𝟏.𝟐𝟐 𝒃𝒂𝒓 and π‘·π‘ΆπŸ = 𝟐.πŸ‘πŸ‘ 𝒃𝒂𝒓.

Calculate π‘ƒ at 750 K (3 points). Hint be sure to convert Kc to Kp first. π‘†π‘‚3

Calculate Kc at 550 K if Ξ”π‘Ÿπ»π‘œ = βˆ’197.8 π‘˜π½ π‘šπ‘œπ‘™βˆ’1 (2 points).

Does the decrease in temperature favour products or reactants at equilibrium (1 point)?


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2022-04-26T12:45:02-0400

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