ππΊπΆπ(π) + πΆπ(π) β ππΊπΆπ(π)
Kc = 6.1 x 104 at 750K. At equilibrium π·πΊπΆπ = π.ππ πππ and π·πΆπ = π.ππ πππ.
Calculate π at 750 K (3 points). Hint be sure to convert Kc to Kp first. ππ3
Calculate Kc at 550 K if Ξππ»π = β197.8 ππ½ πππβ1 (2 points).
Does the decrease in temperature favour products or reactants at equilibrium (1 point)?
The answer to your question is provided in the image:
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