ππΊπΆπ(π) + πΆπ(π) β ππΊπΆπ(π)
Kc = 6.1 x 104Β at 750K. At equilibriumΒ π·πΊπΆπΒ = π.ππ πππΒ andΒ π·πΆπΒ = π.ππ πππ.
CalculateΒ πΒ at 750 K (3 points).Β Hint be sure to convert Kc to Kp first.Β ππ3
Calculate Kc at 550 K ifΒ Ξππ»πΒ = β197.8 ππ½ πππβ1Β (2 points).
Does the decrease in temperature favour products or reactants at equilibrium (1 point)?
The answer to your question is provided in the image:
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