Answer to Question #332615 in General Chemistry for Ivan Ackerman

Question

What is the concentration of a 53.80 mL solution of HBr that is completely titrated by 35.00 mL of a 0.200 M NaOH solution?

Answer 1

Solution:

Balanced chemical equation:

HBr(aq) + NaOH(aq) → NaBr(aq) + H₂O(l)

According to stoichiometry:

Moles of HBr = Moles of NaOH

or:

Molarity of HBr × Volume of HBr = Molarity of NaOH × Volume of NaOH

Therefore,

Molarity of HBr = (Molarity of NaOH × Volume of NaOH) / (Volume of HBr)

Molarity of HBr = (0.200 M × 35.00 mL) / (53.80 mL) = 0.130 M

Molarity of HBr = 0.130 M

Answer: The concentration of HBr solution is 0.130 M