Answer to Question #332540 in General Chemistry for Patrick

Question

1.5 molar,

50 mL nitric acid solution

Volume of solute, mass solute, volume of water

Answer 1

C = n(solute) / V(solution)

n(solute) = V(solution) × C = 0.05 L × 1.5 mol/L = 0.075 mol

m(solute) = n(solute) × Mr(solute) = 0.075 mol × 63.01 g/mol (HNO₃) = 4.73 g

V(HNO₃) = m(HNO₃) / $\rho$(HNO₃) = 4.73 g / 1.51 g/mL = 3.13 mL

V(water) = V(solution) - V(HNO₃) = 50 mL - 3.13 mL = 46.87 mL