Answer to Question #332227 in General Chemistry for John

Question

Write the equilibrium expression, K eq , for each of the following reactions:

1. 2 NO (g) + O 2(g) ⇌2 NO 2(g)

2. 4 HCl (g) + O 2(g) ⇌2 H 2 O (g) + 2 Cl 2(g)

3. NOCl (g) ⇌NO (g) + ½ Cl 2(g)

4. Fe 3+ (aq) + SCN - (aq) ⇌FeSCN 2+ (aq)

5. CaCl 2(s) ⇌Ca 2+ (aq) + 2Cl - (aq)

6. HC 2 H 3 O 2(aq) + H 2 O (l) ⇌ H 3 O + (aq) + C 2 H 3 O 2 - (aq)

7. MgO (s) + CO 2(g) ⇌ MgCO 3(s)

8. C (s) + CO 2(g) + 2Cl 2(g) ⇌ COCl 2(g)

9. Ca 3 (PO 4 ) 2(s) ⇌ 3 Ca 2+ (aq) + 2 PO 4 3- (aq)

10. ZnO (s) + CO (g) ⇌ Zn (s) +CO 2(g)

PLEASE ANSWER MY QUESTION QUICKLY !!

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DEADLINE : 04/23/2022 11 : 00 PM

Answer 1

1. K_eq = [NO₂]² / [O₂][NO]²

2.K_eq = [H₂O]²[Cl₂]² / [O₂][HCl]⁴

3. K_eq = [Cl₂][NO]² / [NOCl]²

4. K_eq = 1

5. K_eq = 1

6. K_eq = 1

7. K_eq = 1/[CO₂]

8. K_eq = [COCl₂] / [CO₂][Cl₂]²

9. K_eq = 1

10. K_eq = [CO₂] / [CO]