Question #331264
what is the concentration of a solution with a volume of 3.3ml that contains 12 grams of ammonium sulfite((NN4)2SO3)
Expert's answer
12 / 116.15 = 0.1033 mol of ammonium sulfite
V = 3.3 mL = 0.0033 L of the solution
Molarity = 0.1033 / 0.0033 = 31.3 M
