Answer to Question #330928 in General Chemistry for Wiseshow

Question

A given mass of nitrogen is 0.12 dm³ at 60⁰C and 1.01×10⁵ Nm–². Find it's pressure at the same temperature if it's volume is changed to 0.24 dm³.

Answer 1

P₁ = 1.01×10⁵ N m^–2

V₁ = 0.12 dm³

T₁ = T₂ = 60°C = constant

P₂ = ???

V₂ = 0.24 dm³

Solution:

Since the temperature and amount of gas remain unchanged, Boyle's law can be used.

Boyle's gas law can be expressed as: P₁V₁ = P₂V₂

To find the final pressure, solve the equation for P₂:

P₂ = P₁V₁ / V₂

P₂ = (1.01×10⁵ N m^–2 × 0.12 dm³) / (0.24 dm³) = 5.05×10⁴ N m^–2

P₂ = 5.05×10⁴ N m^–2

Answer: 5.05×10⁴ N m^–2