Question

Nitrogen gas and hydrogen gas are combined in a reaction to produce ammonia. If 6.0 moles of N2 and 6.0 moles of H2 are present in the mixture, which is the limiting reactant? 

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Answer 1

N₂ + 3H₂ = 2NH₃

Mole ratio N₂ to H₂ is 1 : 3

So, in order for 6.0 mol of N₂ to react 6.0 * 3 = 18.0 mol of H₂ required

We have only 6.0, so, H₂ – limiting