Nitrogen gas and hydrogen gas are combined in a reaction to produce ammonia. If 6.0 moles of N2 and 6.0 moles of H2 are present in the mixture, which is the limiting reactant?
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N2 + 3H2 = 2NH3
Mole ratio N2 to H2 is 1 : 3
So, in order for 6.0 mol of N2 to react 6.0 * 3 = 18.0 mol of H2 required
We have only 6.0, so, H2 – limiting
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