Question

Determine the [H+] , [OH−] , and pH of a solution with a pOH of 2.81 at 25 °C.

[H+]= 

[OH−]= 

pH= 

Answer 1

$[H^+]= 10^{-pH}=10^{-(14-pOH)}=10^{-11.19}=6.46*10^{-12}M$

$[OH^-]= 10^{-pOH}=10^{-2.81}=1.55*10^{-3}M$

$pH=14-pOH=11.19$