Answer to Question #329609 in General Chemistry for niecy

Question

A 25.0 milliliters sample of HNO_{3 (aq) is neutralized by32.1 milliliters of 0.150 M KOH (aq). What is the concentration of the acid? Show a numerical setup}

Answer 1

HNO₃ + KOH = KNO₃ + H₂O

C_m = nV

n(KOH) = 0.150M / 0.0321L = 4.67 mol

n(KOH) = n(HNO₃) = 4.67 mol

C(HNO₃) = 4.67 mol * 0.025 L = 0.117M