Calculate the percent yield for the reaction: P4 (s) + 6 Cl2 (g) → 4 PCl3 (l) if 75.0 g of phosphorus reacts with excess chlorine gas to produce 111.0 g of phosphorus trichloride.
P4 (s) + 6 Cl2 (g) → 4 PCl3 (l)
According to the reaction, n (PCl3) = 4 x n (P4).
n = m / M
M (P4) = 123.9 g/mol
M (PCl3) = 137.3 g/mol
n (P4) = 75/123.9 = 0.61 mol
n (PCl3) = 4 x n (P4) = 4 x 0.61 = 2.4 mol
m (PCl3)theoretical = n x M = 2.4 x 137.3 = 332.4 g
%(PCl3) = 111 / 332.4 x 100 = 33.4%
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