Answer to Question #328912 in General Chemistry for CHI

Question

the mass in grams of HCI needed to react with 12.8g of alumimum

Answer 1

$6HCl+2Al \rightarrow 2AlCl_3+3H_2$

M(Al)=27 g/mol

n(Al)=12.8/27=0.474 mol

n(HCl)=3n(Al)=3(0.474)=1.42 mol

M(HCl)=1+35.5=36.5 g/mol

m(HCl)=36.5 x 1.42=51.91 g