Answer to Question #328889 in General Chemistry for Tesha

Question

Solve the given problem.

What is the molality of a solution prepared from 29.22 grams of NaCl in 2.00

kg of water?

Given: mass of solute = 29.22 g

Mass of solvent = 2 kg

Required: m = ?

Solution: m = mole of solute/kg solvent

n = 29.22 g x 1 mol/ 58.44 g

n = 0.5 mol

m = 0.5 mol/ 2 kg

Final Answer: m = 0.25 mol/kg

Answer 1

Solution: m = mole of solute/kg solvent

n = 29.22 g / 58.44 g/mol = 0.5 mol

m = 0.5 mol / 2 kg = 0.25 mol/kg