Answer to Question #328697 in General Chemistry for rei

Question

What volume (in L) of 0.246 M HNO3 solution is required to react completely with 38.6 mL of 0.0515 M Ba(OH)2?Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O

Answer 1

Solution:

Balanced chemical equation:

Ba(OH)₂ + 2HNO₃ → Ba(NO₃)₂ + 2H₂O

According to stoichiometry:

Moles of Ba(OH)₂ = Moles of HNO₃ / 2

or:

2 × Molarity of Ba(OH)₂ × Volume of Ba(OH)₂ = Molarity of HNO₃ × Volume of HNO₃

Therefore,

Volume of HNO₃ = (2 × Molarity of Ba(OH)₂ × Volume of Ba(OH)₂) / (Molarity of HNO₃)

Volume of HNO₃ = (2 × 0.0515 M × 0.0386 L) / (0.246 M) = 0.0162 L

Volume of HNO₃ = 0.0162 L

Answer: 0.0162 liters of HNO₃ solution is required