What is the heat change (KJ) when 2.31 moles of chlorine reacts with methane?
CH4 + Cl2 = CH3Cl + HCl, "\\Delta" H = -104 kJ (by the chemical literature)
1 mole correspond to (-104) kJ of the heat change, then 2.31 mole correspond x kJ.
x = 2.31 * (-104)/1 = -240.2 kJ.
Answer: -240.2 kJ.
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