An LPG tank contains 11.0 kg of butane gas, (C4H10), in a 25.0 L gas tank. What must be the pressure of the gas inside the tank when the temperature is 25 DEGREES CELCIUS?
PV = nRT
P = nRT / V
n = m/M
P = mRT / MV
P = (11000 * 8.314 * (25 + 273)) / (58 * 0.025) = 18 795 374 Pa = 185.5 atm
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