Answer to Question #326691 in General Chemistry for Richard

Question

Calculate the number of chloride ions in 200 cm cube of 0.5 mol magnesium chloride solution

Answer 1

Solution:

Magnesium Chloride = MgCl₂

MgCl₂ → Mg²⁺ + 2Cl⁻

According to stoichiometry:

1 mol of MgCl₂ produces 2 mol of Cl⁻

Thus, 0.5 mol of MgCl₂ produces:

(0.5 mol MgCl₂) × (2 mol Cl⁻ / 1 mol MgCl₂) = 1 mol Cl⁻

One mole of any substance contains 6.022×10²³ particles.

Therefore,

Number of Cl⁻ ions = (1 mol) × (6.022×10²³ ions / 1 mol) = 6.022×10²³ ions

Number of Cl⁻ ions = 6.022×10²³

Answer: 6.022×10²³ of chloride ions