Answer to Question #325906 in General Chemistry for Chuchutvvvvvv

General Chemistry

Question #325906

How many moles of KBrO3 are required to prepare 0.0700 moles of Br2 according to the reaction: KBrO3 + 5KBr + 6HNO3 6KNO3 + 3Br2 + 3H2O *

A. 0.210

B. 0.0732

C. 0.0704

D. 0.220

Expert's answer

n(KBrO₃)/n(Br₂) = 1/3

n(KBrO₃) = n(Br₂)/3

n(KBrO₃) = 0.0700 moles / 3 = 0.0233 moles

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