A solution is prepared by dissolving 25g of sucrose in 300 g of water. What is the % by mass of the solute? *
A. 6.55%
B. 9.09%
C. 7.69%
D. 8.33%
Answer: C.
ω(sucrose)=mass of sucrosemass of solution=25 g25+300 g=0.0769=7.69%\omega(sucrose)=\dfrac{mass\ of\ sucrose}{mass\ of\ solution}=\dfrac{25\ g}{25+300\ g}=0.0769=7.69\%ω(sucrose)=mass of solutionmass of sucrose=25+300 g25 g=0.0769=7.69%
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